可以说，用户首先必须输入正确的 RE。如果您不知道它是否是特殊字符，您就不能随意转义随机字符。（当然，除非您不希望用户输入 RE，但问题是为什么要使用 RE 进行查询）。

您可以使用 .NET 内置的 Regex.Escape 来实现这一点。从 Microsoft 的示例中复制而来：

string pattern = Regex.Escape("[") + "(.*?)]"; 
string input = "The animal [what kind?] was visible [by whom?] from the window.";

MatchCollection matches = Regex.Matches(input, pattern);
int commentNumber = 0;
Console.WriteLine("{0} produces the following matches:", pattern);
foreach (Match match in matches)
   Console.WriteLine("   {0}: {1}", ++commentNumber, match.Value);  

// This example displays the following output: 
//       \[(.*?)] produces the following matches: 
//          1: [what kind?] 
//          2: [by whom?]

您可以使用 Regex.Escape 来获取用户的输入

string matches = "[]()*";
StringBuilder sMatches = new StringBuilder();
StringBuilder regexPattern = new StringBuilder();
for(int i=0; i<matches.Length; i++)
    sMatches.Append(Regex.Escape(matches[i].ToString()));
regexPattern.AppendFormat("[{0}]+", sMatches.ToString());

Regex regex = new Regex(regexPattern.ToString());
foreach(var m in regex.Matches("ADBSDFS[]()*asdfad"))
    Console.WriteLine("Found: " + m.Value);